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SAP C_ABAPD_2309 Exam Syllabus Topics:

Topic	Details
Topic 1	Core ABAP programming: This topic covers ABAP data types, the ABAP dictionary, modularization, exceptions SAP HANA database tables, and logical expressions, operator precedence.
Topic 2	ABAP core data services and data modeling: It focuses on Core Data Services (CDS) views, SAP HANA database tables, foreign key relationships, and annotations.
Topic 3	ABAP RESTful Application Programming Model: This topic explains the ABAP Restful Application Programming model, ABAP development, and the architecture of the ABAP Restful Application Programming model.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q48-Q53):

NEW QUESTION # 48

When accessing the subclass instance through go_super, what can you do? Note: There are 2 correct answers to this question.

A. Access the inherited public components.
B. Access the inherited private components.
C. Call a subclass specific public method
D. Call inherited public redefined methods.

Answer: A,B

Explanation:
When accessing the subclass instance through go_super, you can do both of the following:
* Access the inherited private components: A subclass inherits all the private attributes and methods of its superclass, unless they are explicitly overridden by the subclass. Therefore, you can access the inherited private components of the superclass through go_super, as long as they are not hidden by other attributes or methods in the subclass12.
* Access the inherited public components: A subclass inherits all the public attributes and methods of its superclass, unless they are explicitly overridden by the subclass. Therefore, you can access the inherited public components of the superclass through go_super, as long as they are not hidden by other attributes or methods in the subclass12.
You cannot do any of the following:
* Call a subclass specific public method: A subclass does not have any public methods that are not inherited from its superclass. Therefore, you cannot call a subclass specific public method through go_super12.
* Call inherited public redefined methods: A subclass does not have any public methods that are redefined from its superclass. Therefore, you cannot call inherited public redefined methods through go_super12.
References: 1: Object Oriented - ABAP Development - Support Wiki 2: Inheritance and Instantiation - ABAP Keyword Documentation

NEW QUESTION # 49
Refer to the Exhibit.

when you attempt to activate the definition, what will be the response?

A. Activation error because the key fields of the union do not match
B. Activation error because the field names of the union do not match
C. Activation successful
D. Activation error because the field types of the union do not match

Answer: B

Explanation:
The response will be an activation error because the field names of the union do not match. This is because the field names of the union must match in order for the definition to be activated. The union operator combines the result sets of two or more queries into a single result set. The queries that are joined by the union operator must have the same number and type of fields, and the fields must have the same names1. In the given code, the field names of the union do not match, because the first query has the fields carrname, connid, cityfrom, and cityto, while the second query has the fields carrname, carrier_id, cityfrom, and cityto. The field connid in the first query does not match the field carrier_id in the second query. Therefore, the definition cannot be activated.

NEW QUESTION # 50
In the assignment, data (gv_result) = 1/8. what will be the data type of gv_result?

A. TYPE P DECIMALS 3
B. TYPE P DECIMALS 2
C. TYPE DEFLOAT 16
D. OTYPE I

Answer: C

Explanation:
The data type of gv_result in the assignment data (gv_result) = 1/8 will be TYPE DECFLOAT 16. This is because the assignment operator (=) in ABAP performs an implicit type conversion from the source type to the target type, according to the following rules12:
If the target type is specified explicitly, the source value is converted to the target type.
If the target type is not specified explicitly, the source type is used as the target type, unless the source type is a literal or an expression, in which case the target type is determined by the following priority order: DECFLOAT34, DECFLOAT16, P, F, I, C, N, X, STRING, XSTRING.
In this case, the target type is not specified explicitly, and the source type is an expression (1/8). Therefore, the target type is determined by the priority order, and the first matching type is DECFLOAT16, which is a decimal floating point type with 16 digits of precision12.

NEW QUESTION # 51
What would be the correct expression to change a given string value 'mr joe doe' into 'JOE' in an ABAP SQL field list?

A. SELECT FROM TABLE dbtabl FIELDS
Of1,
left(lower(substring( 'mr joe doe', 4, 3)), 3) AS f2_left_lo_sub, f3,
B. SELECT FROM TABLE dbtabl FIELDS
Of1,
upper(left( 'mr joe doe', 6)) AS f2_up_left, f3,
C. SELECT FROM TABLE dbtabl FIELDS
Of1,
substring(lower(upper( 'mr joe doe' ) ), 4, 3) AS f2_sub_lo_up, f3,
D. SELECT FROM TABLE dbtabl FIELDS
Of1,
substring(upper('mr joe doe'), 4, 3) AS f2_sub_up, f3,...

Answer: D

Explanation:
Explanation
The correct expression to change a given string value 'mr joe doe' into 'JOE' in an ABAP SQL field list is
C: SELECT FROM TABLE dbtabl FIELDS Of1, substring(upper('mr joe doe'), 4, 3) AS f2_sub_up, f3,...
This expression uses the following SQL functions for strings12:
upper: This function converts all lowercase characters in a string to uppercase. For example, upper('mr joe doe') returns 'MR JOE DOE'.
substring: This function returns a substring of a given string starting from a specified position and with a specified length. For example, substring('MR JOE DOE', 4, 3) returns 'JOE'.
AS: This keyword assigns an alias or a temporary name to a field or an expression in the field list. For example, AS f2_sub_up assigns the name f2_sub_up to the expression substring(upper('mr joe doe'), 4,
3).
You cannot do any of the following:
A: SELECT FROM TABLE dbtabl FIELDS Of1, upper(left( 'mr joe doe', 6)) AS f2_up_left, f3,...:
This expression uses the wrong SQL function for strings to get the desired result. The left function returns the leftmost characters of a string with a specified length, ignoring the trailing blanks. For example, left( 'mr joe doe', 6) returns 'mr joe'. Applying the upper function to this result returns 'MR JOE', which is not the same as 'JOE'.
B: SELECT FROM TABLE dbtabl FIELDS Of1, left(lower(substring( 'mr joe doe', 4, 3)), 3) AS f2_left_lo_sub, f3,...: This expression uses unnecessary and incorrect SQL functions for strings to get the desired result. The lower function converts all uppercase characters in a string to lowercase. For example, lower(substring( 'mr joe doe', 4, 3)) returns 'joe'. Applying the left function to this result with the same length returns 'joe' again, which is not the same as 'JOE'.
D: SELECT FROM TABLE dbtabl FIELDS Of1, substring(lower(upper( 'mr joe doe' ) ), 4, 3) AS f2_sub_lo_up, f3,...: This expression uses unnecessary and incorrect SQL functions for strings to get the desired result. The lower function converts all uppercase characters in a string to lowercase, and the upper function converts all lowercase characters in a string to uppercase. Applying both functions to the same string cancels out the effect of each other and returns the original string. For example, lower(upper( 'mr joe doe' ) ) returns 'mr joe doe'. Applying the substring function to this result returns
'joe', which is not the same as 'JOE'.
References: 1: SQL Functions for Strings - ABAP Keyword Documentation - SAP Online Help 2: sql_func - String Functions - ABAP Keyword Documentation - SAP Online Help

NEW QUESTION # 52
You have two internal tables itab1 and itab2.What is true for using the expression itab1 = corresponding #( itab2 )? Note: There are 2 correct answers to this question.

A. Fields with the same name but with different types may be copied from itab2 to itab1.
B. Fields with the same name and the same type will be copied from itab2 to itab1.
C. itab1 and itab2 must have the same data type.
D. itab1 and itab2 must have at least one field name in common.

Answer: B,D

Explanation:
The expression itab1 = corresponding #( itab2 ) is a constructor expression with the component operator CORRESPONDING that assigns the contents of the internal table itab2 to the internal table itab1. The following statements are true for using this expression:
* B: itab1 and itab2 must have at least one field name in common. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for internal tables. If itab1 and itab2 do not have any field name in common, the expression will not assign any value to itab1 and it will remain initial or unchanged1
* C: Fields with the same name and the same type will be copied from itab2 to itab1. This is because the component operator CORRESPONDING assigns the identically named columns of itab2 to the identically named columns of itab1 by default, according to the rules of MOVE-CORRESPONDING for
* internal tables. If the columns have the same name but different types, the assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1 The following statements are false for using this expression:
* A: Fields with the same name but with different types may be copied from itab2 to itab1. This is not true, as explained in statement C. The assignment will try to perform a conversion between the types, which may result in a loss of precision, a truncation, or a runtime error, depending on the types involved1
* D: itab1 and itab2 must have the same data type. This is not true, as the component operator CORRESPONDING can assign the contents of an internal table of one type to another internal table of a different type, as long as they have at least one field name in common. The target type of the expression is determined by the left-hand side of the assignment, which is itab1 in this case. The expression will create an internal table of the same type as itab1 and assign it to itab11 References: CORRESPONDING - Component Operator - ABAP Keyword Documentation

NEW QUESTION # 53
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